A) 2 cm
B) 4 cm
C) 6 cm
D) 8 cm
Correct Answer: C
Solution :
(c): Given, OP = 10 cm and AM = 8 cm (let M be point of contact for Tangney) \[\because \] \[OM\bot LAM\] (\[\because \] Radius is perpendicular to AM) In right \[\Delta \,OMA,\text{ }O{{A}^{2}}=O{{M}^{2}}+M{{A}^{2}}\] \[\Rightarrow \] \[{{10}^{2}}=O{{M}^{2}}+{{8}^{2}}\] \[\Rightarrow \] \[O{{M}^{2}}=100-64=36\] \[\Rightarrow \] \[OM=6cm\] Hence, radius of the circle is 6 cm.You need to login to perform this action.
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