If OP = 9 cm and PT = 40 cm, find the distance between T and S
A) 28 cm
B) 38 cm
C) 32 cm
D) 24 cm
Correct Answer: C
Solution :
(c): \[{{\left( OS+TS \right)}^{2}}={{40}^{2}}+{{9}^{2}}={{\left( 41 \right)}^{2}}\]\[\Rightarrow \] \[TS=41-9=32\]
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