A) \[6+4\sqrt{3}\ sq.\ units\]
B) \[8+\sqrt{3}\] sq. units
C) \[4+\frac{7\sqrt{3}}{2}\] sq. units
D) \[12+2\sqrt{3}\]sq. units
Correct Answer: A
Solution :
In \[\Delta B{{C}_{1}}M\]; \[BM=({{C}_{1}}M).\,\,\cot 30\] Þ \[BM=\sqrt{3}\] Þ Similarly, \[CN=\sqrt{3}\]and \[MN={{C}_{1}}{{C}_{2}}=1+1=2\] Hence, side \[BC=\sqrt{3}+\sqrt{3}+2=2(1+\sqrt{3})\] Þ Area of equilateral triangle \[=\frac{\sqrt{3}}{4}{{[2(1+\sqrt{3})]}^{2}}\]=\[AB=OA-OB=h(\cot {{15}^{o}}-\cot {{30}^{o}})\]sq units.You need to login to perform this action.
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