A) \[\pi \]
B) \[2\pi \]
C) \[4\pi \]
D) \[6\pi \]
Correct Answer: C
Solution :
Radius of circum-circle (R) \[=\frac{a}{2\sin A}=\frac{b}{2\sin B}=\frac{c}{2\sin C}\] \[R=\frac{b}{2\sin B}=\frac{2}{2\sin 30{}^\circ }=2\] Now, area of circle \[=\pi {{R}^{2}}=4\pi \].You need to login to perform this action.
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