A) 27 g
B) 54 g
C) 49.5 g
D) 31 g
Correct Answer: B
Solution :
\[2Al+\frac{3}{2}{{O}_{2}}\to A{{l}_{2}}{{O}_{3}}\] According to equation \[\frac{3}{2}\] mole of \[{{O}_{2}}\] combines with 2 mole Al. 2 mole Al = 54gmYou need to login to perform this action.
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