A) 23.48
B) 46.96
C) 53.78
D) 71.00
Correct Answer: C
Solution :
\[\underset{2(36+1+31+64)=264}{\mathop{2{{(N{{H}_{4}})}_{2}}HP{{O}_{4}}}}\,\equiv \underset{62+80=142}{\mathop{{{P}_{2}}{{O}_{5}}}}\,\] % of \[{{P}_{2}}{{O}_{5}}=\frac{\text{wt}\text{. of }{{P}_{2}}{{O}_{5}}}{\text{wt of salt}}\times 100\] \[=\frac{142}{264}\times 100=53.78%\].
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