A) 5 ml of 0.1 M
B) 10 ml of 1.1 M
C) 10 ml of 0.5 M
D) 10 ml of 0.02 M
Correct Answer: D
Solution :
\[KMn{{O}_{4}}\] \[FeS{{O}_{4}}\] \[\frac{{{M}_{1}}{{V}_{1}}}{{{n}_{1}}}\] = \[\frac{{{M}_{2}}{{V}_{2}}}{{{n}_{2}}}\]; \[{{M}_{1}}{{V}_{1}}=\frac{{{n}_{1}}}{{{n}_{2}}}{{M}_{2}}{{V}_{2}}\] \[=\frac{2}{10}\times 10\times \frac{1}{10}=\frac{1}{5}=0.2\] For , \[{{M}_{1}}{{V}_{1}}=0.02\times 10=\frac{1}{5}\]
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