question_answer

Equivalent weight of \[KMn{{O}_{4}}\] acting as an oxidant in acidic medium is       [CPMT 1990; MP PET 1999]

A)                 The same as its molecular weight

B)                 Half of its molecular weight 

C)                 One-third of its molecular weight

D)                 One-fifth of its molecular weight

Correct Answer: D

Solution :

\[\underset{+7}{\mathop{2KMn{{O}_{4}}}}\,+3{{H}_{2}}S{{O}_{4}}\to {{K}_{2}}S{{O}_{4}}+\underset{+2}{\mathop{2MnS{{O}_{4}}}}\,+3{{H}_{2}}O+5[O]\] \[\]              \[\text{Eq}\text{. wt}\text{.}=\frac{\text{Mol}\text{. wt}\text{.}}{5}\]