A) \[NaOH+HCl\to NaCl+{{H}_{2}}O\]
B) \[Zn+2HCl\to ZnC{{l}_{2}}+{{H}_{2}}\]
C) \[2KCl{{O}_{3}}\to 2KCl+3{{O}_{2}}\]
D) \[{{H}_{2}}+{{I}_{2}}\to 2HI\]
Correct Answer: C
Solution :
In the given options \[KCl{{O}_{3}}\] undergoes decomposition to form \[KCl\] and \[{{O}_{2}}\].
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