A) 14 gm
B) 28 gm
C) 64.5 gm
D) 56 gm
E) 7 gm
Correct Answer: E
Solution :
\[{{C}_{2}}{{H}_{5}}Cl\]\[\xrightarrow{-HCl}{{C}_{2}}{{H}_{4}}\] 64.5 28 32.25 28 64.5 gm \[{{C}_{2}}{{H}_{5}}Cl\] gives 28 gm of \[{{C}_{2}}{{H}_{4}}\] 32.25 gm \[{{C}_{2}}{{H}_{5}}Cl\] gives \[=\frac{28\times 32.25}{64.5}\] = 14 gm of \[{{C}_{2}}{{H}_{4}}\] Obtained product is 50% so mass of obtained alkene \[=\frac{14}{2}=7\,gm\]
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