JEE Main & Advanced Chemistry Organic Chemistry: Some Basic Principles & Techniques Question Bank Chemical analysis of organic compounds

  • question_answer When 32.25gm ethyl chloride dehydro halogenated, if gives 50%. Alkene, what is the mass of product. (atomic mass of chlorine = 35.5) [Kerala CET 2005]

    A) 14 gm

    B) 28 gm

    C) 64.5 gm

    D) 56 gm

    E) 7 gm

    Correct Answer: E

    Solution :

    \[{{C}_{2}}{{H}_{5}}Cl\]\[\xrightarrow{-HCl}{{C}_{2}}{{H}_{4}}\]    64.5                     28   32.25                    28 64.5 gm \[{{C}_{2}}{{H}_{5}}Cl\] gives 28 gm of \[{{C}_{2}}{{H}_{4}}\] 32.25 gm \[{{C}_{2}}{{H}_{5}}Cl\] gives \[=\frac{28\times 32.25}{64.5}\] = 14 gm of \[{{C}_{2}}{{H}_{4}}\] Obtained product is 50% so mass of obtained alkene \[=\frac{14}{2}=7\,gm\]


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