JEE Main & Advanced Chemistry Organic Chemistry: Some Basic Principles & Techniques Question Bank Chemical analysis of organic compounds

  • question_answer An organic compound has an empirical formula \[C{{H}_{2}}O\], its vapour density is 45. The molecular formula of the compounds is  [DCE  2004]

    A) \[C{{H}_{2}}O\]

    B) \[{{C}_{2}}{{H}_{5}}O\]

    C) \[{{C}_{2}}{{H}_{2}}O\]

    D) \[{{C}_{3}}{{H}_{6}}{{O}_{3}}\]

    Correct Answer: D

    Solution :

    Mol. wt = 2 \[\times \] Vap. Density \[=2\times 45=90\] Empirical formula weight \[=12+2+16=30\] \[\therefore \,\,\,n=\frac{\text{mol}\text{. wt}\text{.}}{\text{empirical formula wt}\text{.}}\] \[=\frac{90}{30}=3\] \[\therefore \]  Molecular formula of the compounds \[={{(C{{H}_{2}}O)}_{3}}\]\[={{C}_{3}}{{H}_{6}}{{O}_{3}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner