• # question_answer A compound has an empirical formula ${{C}_{2}}{{H}_{4}}O$. An independent analysis gave a value of 132.16 for its molecular mass. What is the correct molecular formula [Kerala PMT 2004] A) ${{C}_{4}}{{H}_{4}}{{O}_{5}}$ B) ${{C}_{10}}{{H}_{12}}$ C) ${{C}_{7}}{{O}_{3}}$ D) ${{C}_{6}}{{H}_{12}}{{O}_{3}}$ E) ${{C}_{4}}{{H}_{8}}{{O}_{5}}$

Empirical formula weight ${{C}_{2}}{{H}_{4}}O$ $=(12\times 2+4+16)=44$ Molecular formula $=\frac{\text{mol}\text{. wt}}{\text{eq}\text{. formula wt}\text{.}}\times$ Emp. Formula $=\frac{132.1}{44}\times \text{Emperical formula}$ $=3\times {{C}_{2}}{{H}_{4}}O={{C}_{6}}{{H}_{12}}{{O}_{3}}$