• # question_answer The ammonia evolved from the treatment of 0.30 g of an organic compound for the estimation of nitrogen was passed in 100 mL of 0.1 M sulphuric acid. The excess of acid required 20 mL of 0.5 M sodium hydroxide solution for complete neutralization. The organic compound is [AIEEE 2004] A) Urea B) Benzamide C) Acetamide D) Thiourea

Equivalent of $N{{H}_{3}}$ evolved $=\frac{100\times 0.1\times 2}{1000}-\frac{20\times 0.5}{1000}$ $=\frac{1}{100}$ percent of nitrogen in the unknown organic compound $=\frac{1}{100}\times \frac{14}{0.3}\times 100=46.6$% percent of nitrogen in urea ${{(N{{H}_{2}})}_{2}}CO$ $=\frac{14\times 2}{60}\times 100=46.6$% $\therefore$ The compound must be urea.