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JEE Main & Advanced Chemistry Organic Chemistry: Some Basic Principles & Techniques / कार्बनिक रसायन : कुछ मूलभूत सिद्धांत एवं तकन Question Bank Chemical analysis of organic compounds

  • question_answer
    The ammonia evolved from the treatment of 0.30 g of an organic compound for the estimation of nitrogen was passed in 100 mL of 0.1 M sulphuric acid. The excess of acid required 20 mL of 0.5 M sodium hydroxide solution for complete neutralization. The organic compound is [AIEEE 2004]

    A) Urea

    B) Benzamide

    C) Acetamide

    D) Thiourea

    Correct Answer: A

    Solution :

    Equivalent of \[N{{H}_{3}}\] evolved \[=\frac{100\times 0.1\times 2}{1000}-\frac{20\times 0.5}{1000}\] \[=\frac{1}{100}\] percent of nitrogen in the unknown organic compound \[=\frac{1}{100}\times \frac{14}{0.3}\times 100=46.6\]% percent of nitrogen in urea \[{{(N{{H}_{2}})}_{2}}CO\] \[=\frac{14\times 2}{60}\times 100=46.6\]% \[\therefore \] The compound must be urea.


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