• # question_answer An organic compound on analysis gave C = 48 gm, H =  8 gm and N = 56 gm. Volume of 1.0 g of the compound was found to be 200 ml at NTP. Molecular formula of the compound is [MP PET 1986] A) ${{C}_{4}}{{H}_{8}}{{N}_{4}}$ B) ${{C}_{2}}{{H}_{4}}{{N}_{2}}$ C) ${{C}_{12}}{{H}_{24}}{{N}_{12}}$ D) ${{C}_{16}}{{H}_{32}}{{N}_{16}}$

Empirical formula = $C{{H}_{2}}N$ Empirical formula mass = 28 Now, 200 ml of compound = 1 gm 22400 ml of compound $\frac{1}{200}\times 22400=112$ $n=\frac{12}{2}=6$ Therefore, Molecular formula $={{(C{{H}_{2}}N)}_{4}}={{C}_{4}}{{H}_{8}}{{N}_{4}}$.