• # question_answer In Victor Mayer?s method 0.2 gm of an organic substance displaced 56 ml of air at STP the molecular weight of the compound [Kerala (Med.) 2003] A) 56 B) 112 C) 80 D) 28

Molecular mass $n=\frac{M.wt}{E.F.wt}=\frac{146}{73}=2$ $=\frac{0.2}{56}\times 22400=80$.