JEE Main & Advanced Chemistry Organic Chemistry: Some Basic Principles & Techniques Question Bank Chemical analysis of organic compounds

  • question_answer
    Empirical formula of a compound is \[C{{H}_{2}}O\] and its vapour density is 30. Molecular formula of the compound is [MP PMT 1993; AIIMS 1998; CBSE PMT 2000; KCET (Med.) 2000; Pb. PMT 2000]

    A) \[{{C}_{3}}{{H}_{6}}{{O}_{3}}\]

    B) \[{{C}_{2}}{{H}_{4}}{{O}_{2}}\]

    C) \[{{C}_{2}}{{H}_{4}}O\]

    D) \[C{{H}_{2}}O\]

    Correct Answer: B

    Solution :

    Empirical Formula = \[C{{H}_{2}}O\] Empirical formula mass = 12 + 2 + 16 = 30 Mol. Mass = 2 × V.D. = 2 × 30 = 60 \[n=\frac{\text{Mol}\text{.}\,\text{mass}}{\text{Emperical}\,\,\text{mass}}=\frac{60}{30}=2\] Molecular formula = \[{{\text{(Emperical formula)}}_{n}}\]                        = \[{{(C{{H}_{2}}O)}_{2}}\] = \[{{C}_{2}}{{H}_{4}}{{O}_{2}}\].


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