JEE Main & Advanced Chemistry Organic Chemistry: Some Basic Principles & Techniques Question Bank Chemical analysis of organic compounds

  • question_answer An organic compound contains \[C=36%\] \[H=6%\] and rest oxygen. Its Empirical formula is

    A) \[C{{H}_{2}}O\]

    B) \[{{C}_{2}}{{H}_{3}}{{O}_{3}}\]

    C) \[C{{H}_{2}}{{O}_{2}}\]

    D) \[{{C}_{2}}{{H}_{2}}{{O}_{2}}\]

    Correct Answer: A

    Solution :

    Element      %        No. of Moles       Simple Ratio
    C 36 36/12 = 3 3/3 = 1
    H 6 6/1 = 6 6/3 = 2
    O 58 58/16 = 3.62 3.62/3 = 1
    Therefore, Empirical formula = \[C{{H}_{2}}O\]


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