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JEE Main & Advanced Chemistry Organic Chemistry: Some Basic Principles & Techniques / कार्बनिक रसायन : कुछ मूलभूत सिद्धांत एवं तकन Question Bank Chemical analysis of organic compounds

  • question_answer
    If a compound on analysis was found to contain C = 18.5%, H = 1.55%, Cl = 55.04% and O = 24.81%, then its empirical formula is [AIIMS 1998]

    A) \[CHClO\]

    B) \[C{{H}_{2}}ClO\]

    C) \[{{C}_{2}}{{H}_{2}}OCl\]

    D) \[ClC{{H}_{2}}O\]

    Correct Answer: A

    Solution :

    Elements        No. of moles        Simple ratio C = 18.5%         18.5/12      Þ1.54      1 H = 1.55%         1.55/1        Þ1.55      1 Cl = 55.04%      55.04/35.5 Þ1.55       1 O = 24.81%      24.81/16     Þ1.55      1 Hence, formula = \[CHClO\].


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