JEE Main & Advanced Chemistry Organic Chemistry: Some Basic Principles & Techniques Question Bank Chemical analysis of organic compounds

  • question_answer An organic compound with C = 40% and H = 6.7% will have the empirical formula [MP PET 1999; JIPMER 2002]

    A) \[C{{H}_{2}}\]

    B) \[C{{H}_{2}}O\]

    C) \[{{C}_{3}}{{H}_{6}}{{O}_{3}}\]

    D) \[{{C}_{2}}{{H}_{4}}{{O}_{2}}\]

    Correct Answer: B

    Solution :

    Elements            No. of moles       Simple ratio
    C = 40% 40/12 3.33 1
    H = 6.7% 6.7/1 6.7 2
    O = 53.3% 5.33/16 3.33 1
    Thus, Empirical formula = \[C{{H}_{2}}O\].


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