A) CO
B) \[{{C}_{4}}{{O}_{3}}\]
C) \[{{C}_{12}}{{O}_{9}}\]
D) \[{{C}_{3}}{{O}_{3}}\]
Correct Answer: C
Solution :
Elements Simple ratio \[C\,\,\,\,\,=\,\,\,\,\,\,\,50\,\,\,\,\,\,\,\,\,\,\,\,50/12\,\,\,\,=\,\,\,\,4\] \[(C{{H}_{2}}O)\] Empirical formula = \[{{C}_{4}}{{O}_{3}}\] Empirical formula mass = 96 \[n\,\,=\,\,\frac{290}{96}=3\] Molecular formula = \[{{({{C}_{4}}{{O}_{3}})}_{3}}={{C}_{12}}{{O}_{9}}\].
You need to login to perform this action.
You will be redirected in
3 sec
