• # question_answer An organic compound gave C = 92.31% and $H=7.69%$. If molecular weight of the compound is 78, its molecular formula is A) ${{C}_{6}}{{H}_{6}}$ B) ${{C}_{7}}{{H}_{7}}$ C) ${{C}_{6}}{{H}_{18}}$ D) ${{C}_{8}}{{H}_{20}}$

Hence, CH Empirical formula mass of CH = 13 $n=\frac{\text{Mol}\text{. mass}}{\text{Emp}\text{.}\,\text{mass}}=\frac{78}{13}=6$ Molecular formula = ${{(CH)}_{6}}={{C}_{6}}{{H}_{6}}$.