• # question_answer 60 g of a compound on analysis gave $C=24\text{ }g,$ $H=4\text{ }g$ and O = 32 g. Its Empirical formula is [CPMT 1971, 81] A) ${{C}_{2}}{{H}_{4}}{{O}_{2}}$ B) ${{C}_{2}}{{H}_{2}}O$ C) $C{{H}_{2}}{{O}_{2}}$ D) $C{{H}_{2}}O$

Therefore $C{{H}_{2}}O$.