JEE Main & Advanced Chemistry Organic Chemistry: Some Basic Principles & Techniques Question Bank Chemical analysis of organic compounds

  • question_answer 60 g of a compound on analysis gave \[C=24\text{ }g,\] \[H=4\text{ }g\] and O = 32 g. Its Empirical formula is [CPMT 1971, 81]

    A) \[{{C}_{2}}{{H}_{4}}{{O}_{2}}\]

    B) \[{{C}_{2}}{{H}_{2}}O\]

    C) \[C{{H}_{2}}{{O}_{2}}\]

    D) \[C{{H}_{2}}O\]

    Correct Answer: D

    Solution :

    Element                No. of Moles      Simple Ratio
    C = 24 24/12 = 2 1
    H = 4 4/1 = 4 2
    O = 32 32/16 = 2 1
    Therefore \[C{{H}_{2}}O\].


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