JEE Main & Advanced Chemistry Organic Chemistry: Some Basic Principles & Techniques Question Bank Chemical analysis of organic compounds

  • question_answer An organic compound contains \[C=74.0%,\] \[H=8.65%\] and \[N=17.3%\]. Its Empirical formula is [MP PMT 1986]

    A) \[{{C}_{5}}{{H}_{8}}N\]

    B) \[{{C}_{10}}{{H}_{12}}N\]

    C) \[{{C}_{5}}{{H}_{7}}N\]

    D) \[{{C}_{10}}{{H}_{14}}N\]

    Correct Answer: C

    Solution :

    Element       No. of Moles         Simple Ratio
    C = 74 74/12 = 6.1 6.1/1.2 = 5.08 or 5
    H = 8.65 8.65/1= 8.65 8.6/1.2 = 7.16 or 7
    N = 17.3 17.3/14 = 1.2 1.2/1.2 = 1 or 1
    Therefore Empirical formula \[={{C}_{5}}{{H}_{7}}N\].


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