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JEE Main & Advanced Chemistry Organic Chemistry: Some Basic Principles & Techniques / कार्बनिक रसायन : कुछ मूलभूत सिद्धांत एवं तकन Question Bank Chemical analysis of organic compounds

  • question_answer
    In Carius method 0.099 g organic compound gave 0.287 g \[AgCl\]. The percentage of chlorine in the compound will be

    A) 28.6

    B) 71.7

    C) 35.4

    D) 64.2

    Correct Answer: B

    Solution :

    % of chlorine = \[\frac{35.5}{143.5}\times \frac{\text{Mass of }AgCl}{\text{Mass of substance}}\times 100\] = \[\frac{35.5}{143.5}\times \frac{0.287}{\text{0}\text{.099}}\times 100=71.71%\].


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