A) The particle is stationary and magnetid field is perpendicular.
B) The particle is moving and magnetic field is perpendicular to the velocity.
C) The particle is stationary and magnetic field is parallel.
D) The particle is moving and magnetic field is parallel to velocity.
Correct Answer: B
Solution :
(b) The particle is moving and magnetic field is perpendicular to the velocity. Magnetic force on the charged particle q is \[{{\overrightarrow{F}}_{m}}=q(\overrightarrow{v}\times \overrightarrow{B})\] or \[{{F}_{m}}=qvB\,\sin \,\theta \] Where \[\theta \] is the angle between \[\overrightarrow{v}\] and \[\overrightarrow{B}\]. Out of the given cases, only in case (b) it will experience the force while in other cases it will experience no force.
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