A) \[C{{H}_{4}}\]
B) \[{{C}_{2}}{{H}_{2}}\]
C) \[{{C}_{2}}{{H}_{6}}\]
D) \[C{{O}_{2}}\]
Correct Answer: A
Solution :
\[A{{l}_{4}}{{C}_{3}}+12{{H}_{2}}O\to 3C{{H}_{4}}+4Al{{(OH)}_{3}}\]
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