JEE Main & Advanced Chemistry GOC Question Bank Bonding and hybridisation inorganic compounds

  • question_answer The compound in which carbon uses only its \[s{{p}^{3}}\] hybrid orbitals for bond formation is [IIT-JEE 1989]

    A) \[HCOOH\]

    B) \[{{(N{{H}_{2}})}_{2}}CO\]

    C) \[{{(C{{H}_{3}})}_{3}}COH\]

    D) \[{{(C{{H}_{3}})}_{3}}CHO\]

    Correct Answer: C

    Solution :

               \[\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\underset{\underset{\underset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,\,\,\,\,\,}{\mathop{|\,\,\,\,\,\,\,\,\,\,\,\,\,}}\,}{\overset{\overset{\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,\,\,\,\,\,\,}{\mathop{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,}}\,}{\mathop{{{C}^{s{{p}^{3}}}}-}}}\,OH\] All the carbon atoms are \[s{{p}^{3}}\] hybridized.


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