• # question_answer In the reaction $\begin{matrix} Br \\ H \\ \end{matrix}>\underset{1}{\mathop{C}}\,=\underset{2}{\mathop{C}}\,<\begin{matrix} Br \\ H \\ \end{matrix}\overset{{{H}_{2}}}{\mathop{\xrightarrow[\text{Catalyst}]{}}}\,\underset{3}{\mathop{BrC{{H}_{2}}}}\,\underset{4}{\mathop{C{{H}_{2}}Br}}\,$ The hybridisation states of carbon atoms 1, 2, 3, 4 are [MP PET 1994] A) 1 and 2 $s{{p}^{2}};$ 3 and 4 $s{{p}^{3}}$ B) 1 and 2 $s{{p}^{2}};$ 3 and 4 $sp$ C) 1, 2, 3 and 4 $sp$ D) 1, 2 $s{{p}^{3}};$ 3, 4 $s{{p}^{2}}$

$\underset{\,\,\,s{{p}^{2}}\,\,\,\,\,\,s{{p}^{2}}}{\mathop{Br-\overset{1}{\mathop{CH=}}\,\overset{2}{\mathop{CH}}\,-Br}}\,\,\underset{\text{Catalyst}}{\mathop{\xrightarrow{{{H}_{2}}}}}\,Br-\underset{s{{p}^{3}}}{\overset{3\,\,\,\,\,}{\mathop{C{{H}_{2}}}}}\,-\underset{s{{p}^{3}}}{\mathop{\overset{4\,\,\,\,\,\,}{\mathop{C{{H}_{2}}}}\,}}\,-Br$