A) 70
B) 100
C) 170
D) 270
Correct Answer: C
Solution :
First ionization potential of \[Li=5.4eV\] Electron affinity of \[Cl=3.61eV\] We have \[\Delta H=I.P.-E.A.\] \[=5.4-3.61=1.80eV=1.80\times 1.6\times {{10}^{-22}}kJ\] \[\Delta H=2.86\times {{10}^{-22}}kJ,\] for 1mol Avogadro?s number \[=6.02\times {{10}^{23}}\]. \[\Delta H=2.86\times {{10}^{-22}}\times 6.02\times {{10}^{23}}=170\,kJ/mole.\]You need to login to perform this action.
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