JEE Main & Advanced Mathematics Pair of Straight Lines Question Bank Bisectors of the angle between the lines, Point of intersection of the lines

  • question_answer
    The equation of the bisectors of angle between the lines represented by equation \[{{(y-mx)}^{2}}={{(x+my)}^{2}}\]is

    A)            \[m{{x}^{2}}+({{m}^{2}}-1)xy-m{{y}^{2}}=0\]           

    B)            \[m{{x}^{2}}-({{m}^{2}}-1)xy-m{{y}^{2}}=0\]

    C)            \[m{{x}^{2}}+({{m}^{2}}-1)xy+m{{y}^{2}}=0\]          

    D)            None of these

    Correct Answer: A

    Solution :

               The equation is                    \[{{y}^{2}}+{{m}^{2}}{{x}^{2}}-2mxy-{{x}^{2}}-{{m}^{2}}{{y}^{2}}-2mxy=0\]            \[\Rightarrow {{x}^{2}}({{m}^{2}}-1)+{{y}^{2}}(1-{{m}^{2}})-4mxy=0\]            Therefore, the equation of bisectors is \[\frac{{{x}^{2}}-{{y}^{2}}}{xy}\]            \[=\frac{({{m}^{2}}-1)-(1-{{m}^{2}})}{-2m}\]\[\Rightarrow m{{x}^{2}}+({{m}^{2}}-1)xy-m{{y}^{2}}=0\].


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