JEE Main & Advanced Mathematics Pair of Straight Lines Question Bank Bisectors of the angle between the lines, Point of intersection of the lines

  • question_answer The point of intersection of the lines represented by the equation \[2{{x}^{2}}+3{{y}^{2}}+7xy+8x+14y+8=0\] is

    A)            (0, 2)                                        

    B)            (1, 2)

    C)            (-2, 0)                                      

    D)            (-2, 1)

    Correct Answer: C

    Solution :

               If the equation is general equation            \[a{{x}^{2}}+2hxy+b{{y}^{2}}+2gx+2fy+c=0\]            Then points of intersection are given by \[\left( \frac{hf-bg}{ab-{{h}^{2}}},\frac{hg-af}{ab-{{h}^{2}}} \right)\]            Hence point is\[(-2,\text{ }0)\].


You need to login to perform this action.
You will be redirected in 3 sec spinner