A) \[{{(a-b)}^{2}}={{h}^{2}}\]
B) \[{{(a+b)}^{2}}={{h}^{2}}\]
C) \[{{(a-b)}^{2}}=4{{h}^{2}}\]
D) \[{{(a+b)}^{2}}=4{{h}^{2}}\]
Correct Answer: D
Solution :
Let one line be \[x+y=0\,\,\,\Rightarrow \,\,{{m}_{1}}=-1\] and we know that \[{{m}_{1}}+{{m}_{2}}=-\frac{2h}{b}\] .....(i) and \[{{m}_{1}}{{m}_{2}}=\frac{a}{b}\] .....(ii) Therefore from (ii), \[{{m}_{2}}=-\frac{a}{b}\] \[\Rightarrow -1-\frac{a}{b}=\frac{-2h}{b}\Rightarrow {{(a+b)}^{2}}=4{{h}^{2}}\].
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