A) \[y=x\]
B) \[y=-x\]
C) \[y=mx\]
D) \[my=x\]
Correct Answer: C
Solution :
Equation of bisectors of angle between the lines represented by \[p{{x}^{2}}-2rxy+q{{y}^{2}}=0\]is \[\frac{{{x}^{2}}-{{y}^{2}}}{p-q}=\frac{xy}{-r}\] ..... (i) On putting \[y=mx\]in (i), we get \[\frac{1-{{m}^{2}}}{p-q}=\frac{m}{-r}\]\[\Rightarrow r(1-{{m}^{2}})+m(p-q)=0\].You need to login to perform this action.
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