A) (0, 2)
B) (1, 2)
C) (-2, 0)
D) (-2, 1)
Correct Answer: C
Solution :
If the equation is general equation \[a{{x}^{2}}+2hxy+b{{y}^{2}}+2gx+2fy+c=0\] Then points of intersection are given by \[\left( \frac{hf-bg}{ab-{{h}^{2}}},\frac{hg-af}{ab-{{h}^{2}}} \right)\] Hence point is\[(-2,\text{ }0)\].You need to login to perform this action.
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