JEE Main & Advanced Mathematics Binomial Theorem and Mathematical Induction Question Bank Binomial theorem for any index

  • question_answer
    If \[|x|>1\], then \[{{(1+x)}^{-2}}\] =

    A) \[1-2x+3{{x}^{2}}-....\]

    B) \[1+2x+3{{x}^{2}}+\]....

    C) \[1-\frac{2}{x}+\frac{3}{{{x}^{2}}}-....\]

    D) \[\frac{1}{{{x}^{2}}}-\frac{2}{{{x}^{3}}}+\frac{3}{{{x}^{4}}}-\]...

    Correct Answer: D

    Solution :

    Given that |x|>1. So given expression can be written as \[{{x}^{-2}}{{\left( 1+\frac{1}{x} \right)}^{-2}}={{x}^{-2}}\left[ 1-\frac{2}{x}+\frac{3}{{{x}^{2}}}-\frac{4}{{{x}^{3}}}+.... \right]\]                       \[=\left[ \frac{1}{{{x}^{2}}}-\frac{2}{{{x}^{3}}}+\frac{3}{{{x}^{4}}}-\frac{4}{{{x}^{5}}}+.... \right]\]


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