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JEE Main & Advanced Mathematics Binomial Theorem and Mathematical Induction Question Bank Binomial theorem for any index

  • question_answer
    If x is positive, the first negative term in the expansion of \[{{(1+x)}^{27\,/\,5}}\] is [AIEEE 2003]

    A) 7th term

    B) 5th term

    C) 8th term

    D) 6th term

    Correct Answer: C

    Solution :

    \[{{(1+x)}^{27/5}}\] \[{{T}_{r+1}}=\frac{n(n-1)(n-2)......(n-r+1)}{r!}{{(x)}^{r}}\] For first negative term\[n-r+1<0\]; \[r>\frac{32}{5}\] .   \ First negative term is 8th term.


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