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JEE Main & Advanced Physics Wave Mechanics Question Bank Beats

  • question_answer
    Beats are produced by two waves                    \[{{y}_{1}}=a\sin 1000\,\pi t,\] \[{{y}_{2}}=a\sin 998\pi t\]            The number of beats heard/sec is                                                [KCET 1998]

    A)            0    

    B)            2

    C)            1    

    D)            4

    Correct Answer: C

    Solution :

                       \[{{n}_{1}}=\frac{1000\pi }{2\pi }=500Hz\] and \[{{n}_{2}}=\frac{998\pi }{2\pi }=499\]Hz                    Hence beat frequency = \[{{n}_{1}}-{{n}_{2}}=1\]


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