A) \[105\,{{s}^{-1}}\]
B) \[205\,{{s}^{-1}}\]
C) \[95\,{{s}^{-1}}\]
D) \[100\,{{s}^{-1}}\]
Correct Answer: A
Solution :
Frequency of the source = 100 ± 5 = 105 Hz or 95 Hz. Second harmonic of the source = 210 Hz or 190 Hz. As the second harmonic gives 5 beats/sec with sound of frequency 205 Hz, the second harmonic should be 210 Hz. Þ Frequency of the source = 105 Hz.
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