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JEE Main & Advanced Physics Wave Mechanics Question Bank Basics of Mechanical Waves

  • question_answer
    Velocity of sound waves in air is 330 m/sec. For a particular sound in air, a path difference of 40 cm is equivalent to a phase difference of 1.6p. The frequency of this wave is [CBSE PMT 1990]

    A)            165 Hz                                     

    B)            150 Hz

    C)            660 Hz                                     

    D)            330 Hz

    Correct Answer: C

    Solution :

               Phase difference =\[\frac{2\pi }{\lambda }\times \] path difference                    Þ\[1.6\pi =\frac{2\pi }{\lambda }\times 40\]\[\Rightarrow \]\[\lambda =50\]\[cm\]= 0.5m                    Þ \[v=n\lambda \]Þ \[330=0.5\times n\Rightarrow n=660\,Hz\]


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