A) 35°C
B) 48°C
C) 65°C
D) 14°C
Correct Answer: D
Solution :
\[v=\sqrt{\frac{\gamma \,RT}{M}}\]Þ\[\frac{{{T}_{N}}}{{{T}_{0}}}=\frac{{{M}_{N}}}{{{M}_{0}}}\]Þ \[\frac{{{T}_{N}}}{273+55}=\frac{14}{16}=\frac{7}{8}\] Þ \[{{T}_{N}}=287K=14{}^\circ C\]
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