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JEE Main & Advanced Physics Wave Mechanics Question Bank Basics of Mechanical Waves

  • question_answer
    The temperature at which the speed of sound in air becomes double of its value at \[{{0}^{o}}C\] is        [AIEEE 2002]

    A)            273K                                        

    B)            546K

    C)            1092K                                      

    D)            0K

    Correct Answer: C

    Solution :

                \[v\propto \sqrt{T}\]Þ\[\sqrt{\frac{{{T}_{2}}}{{{T}_{1}}}}=\frac{{{v}_{2}}}{{{v}_{1}}}\Rightarrow {{T}_{2}}={{T}_{1}}{{\left( \frac{{{v}_{2}}}{{{v}_{1}}} \right)}^{2}}\]                    \[\Rightarrow {{T}_{2}}=273\times 4=1092K\]


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