JEE Main & Advanced Physics Wave Mechanics Question Bank Basics of Mechanical Waves

  • question_answer
    When the temperature of an ideal gas is increased by 600 K, the velocity of sound in the gas becomes \[\sqrt{3}\] times the initial velocity in it. The initial temperature of the gas is [EAMCET (Med.) 2000]

    A)            \[-{{73}^{o}}C\]                  

    B)            \[{{27}^{o}}C\]

    C)            \[{{127}^{o}}C\]                  

    D)            \[{{327}^{o}}C\]

    Correct Answer: B

    Solution :

                By using \[v=\sqrt{\frac{\gamma RT}{M}}\Rightarrow v\propto \sqrt{T}\]                    \[\frac{{{v}_{2}}}{{{v}_{1}}}=\sqrt{\frac{{{T}_{2}}}{{{T}_{1}}}}=\sqrt{\frac{T+600}{T}}=\sqrt{3}\Rightarrow T=300\,K\,={{27}^{o}}C\]


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