JEE Main & Advanced Physics Wave Mechanics Question Bank Basics of Mechanical Waves

  • question_answer
    If velocity of sound in a gas is 360 m/s and the distance between a compression and the nearest rarefaction is 1m, then the frequency of sound is                                [KCET 1999]

    A)            90 Hz                                       

    B)            180 Hz

    C)            360 Hz                                     

    D)            720 Hz

    Correct Answer: B

    Solution :

     Distance between a compression and the nearest rarefaction is \[\frac{\lambda }{2}=1m\,.\] Hence \[n=\frac{v}{\lambda }=\frac{360}{2}=180\,Hz\].


You need to login to perform this action.
You will be redirected in 3 sec spinner