JEE Main & Advanced Physics Wave Mechanics Question Bank Basics of Mechanical Waves

  • question_answer
    A stone is dropped into a lake from a tower 500 metre high. The sound of the splash will be heard by the man approximately after [CPMT 1992; JIPMER 2001, 02;  Kerala PMT 2005]

    A)            11.5 seconds                        

    B)            21 seconds

    C)            10 seconds                            

    D)            14 seconds

    Correct Answer: A

    Solution :

               The time taken by the stone to reach the lake                    \[{{t}_{1}}=\sqrt{\left( \frac{2h}{g} \right)}=\sqrt{\left( \frac{2\times 500}{10} \right)}=10\,sec\] (Using \[h=ut+\frac{1}{2}g{{t}^{2}}\]) Now time taken by sound from lake to the man \[{{t}_{2}}=\frac{h}{v}=\frac{500}{340}\approx 1.5\sec \] Þ Total time \[={{t}_{1}}+{{t}_{2}}=10+1.5=11.5\sec .\]


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