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JEE Main & Advanced Chemistry Coordination Chemistry Question Bank Basic Terms

  • question_answer
    Given the molecular formula of the hexa coordinated complexes A \[CoC{{l}_{3}}.6N{{H}_{3}}\] B \[CoC{{l}_{3}}.5N{{H}_{3}}\] C \[CoC{{l}_{3}}.4N{{H}_{3}}\]. If the number of co-ordinated \[N{{H}_{3}}\] molecules in A, B and C respectively are 6, 5 and 4, the primary valency in A, B and C are: [DCE 2003]

    A) 6, 5, 4

    B) 3, 2, 1

    C) 0, 1, 2

    D) 3, 3, 3

    Correct Answer: B

    Solution :

    The complexes can be written as follows \[\underset{\text{(A)}}{\mathop{[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}}}\,\,\underset{\text{(B)}}{\mathop{[Co{{(N{{H}_{3}})}_{5}}Cl]C{{l}_{2}}}}\,\]\[\underset{\text{(C)}}{\mathop{[Co{{(N{{H}_{3}})}_{4}}C{{l}_{4}}]Cl}}\,\] Hence, number of primary valencies are 3, 2 and 1 respectively.


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