A) 2
B) 6
C) 5
D) 4
Correct Answer: B
Solution :
\[[Co\,{{(en)}_{2}}B{{r}_{2}}]\,C{{l}_{2}}\] \[C.N.\,\text{of }\,Co=\] 2 × number of bidentate ligand +1×number of monodentate ligand =2× 2 + 1× 2 = 6.
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