JEE Main & Advanced Chemistry Redox Reactions / रेडॉक्स अभिक्रियाएँ Question Bank Auto oxidation and Disproportionation

  • question_answer
    The equivalent weight of phosphoric acid \[({{H}_{3}}P{{O}_{4}})\] in the reaction \[NaOH+{{H}_{3}}P{{O}_{4}}\to Na{{H}_{2}}P{{O}_{4}}+{{H}_{2}}O\] is                                                                 [AIIMS 1999]

    A)                 25          

    B)                 49

    C)                 59          

    D)                 98

    Correct Answer: D

    Solution :

           Molecular weight of \[{{H}_{3}}P{{O}_{4}}\] is 98 and change in            its valency  = 1 equivalent wt. of \[{{H}_{3}}P{{O}_{4}}\]                                                   \[=\frac{\text{Molecular}\,\text{weight}}{\text{Change}\,\,\text{in}\,\,\text{valency}}=\frac{98}{1}=98\].


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