A) \[Pb\]
B) \[Zn\]
C) \[Al\]
D) \[Sn\]
Correct Answer: B
Solution :
\[Z{{n}^{2+}}/Zn.\,{{E}^{o}}=-0.76\,V\] \[A{{l}^{3+}}/Al\,\,\,\,\,\,\,\,{{E}^{o}}=-1.662\] \[S{{n}^{2+}}/Sn\,\,\,\,\,{{E}^{o}}=-0.136\] \[P{{b}^{2+}}/Pb\,\,\,\,\,{{E}^{o}}=-0.126\] In galvanizing action \[Zn\] is coated over iron.
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