JEE Main & Advanced Chemistry Redox Reactions / रेडॉक्स अभिक्रियाएँ Question Bank Auto oxidation and Disproportionation

  • question_answer
    In alkaline medium \[Cl{{O}_{2}}\] oxidize \[{{H}_{2}}{{O}_{2}}\] in \[{{O}_{2}}\] and reduced itself in \[C{{l}^{-}}\] then how many mole of \[{{H}_{2}}{{O}_{2}}\] will oxidize by one mole of \[Cl{{O}_{2}}\]        [Kerala CET 2005]

    A)                 1.0         

    B)                 1.5

    C)                 2.5         

    D)                 3.5

    E)                 5.0

    Correct Answer: C

    Solution :

                                             \[Cl{{O}_{2}}\to C{{l}^{-}}\]                            \[Cl{{O}_{2}}+2{{H}_{2}}O+5e\to C{{l}^{-}}+4O{{H}^{-}}\]                                              \[{{H}_{2}}{{O}_{2}}\to {{O}_{2}}\]                                  \[{{H}_{2}}{{O}_{2}}+2O{{H}^{-}}\to {{O}_{2}}+2{{H}_{2}}O+2e\]                             \[Cl{{O}_{2}}+2{{H}_{2}}O+5e\to C{{l}^{-}}+4O{{H}^{-}}]\times 2\]                                  \[{{H}_{2}}{{O}_{2}}+2O{{H}^{-}}\to {{O}_{2}}+2{{H}_{2}}O+2e]\times 2\]                    \[2Cl{{O}_{2}}+5{{H}_{2}}{{O}_{2}}+2O{{H}^{-}}\to 2C{{l}^{-}}+5{{O}_{2}}+5{{H}_{2}}O\]                                              \[2Cl{{O}_{2}}\equiv 5{{H}_{2}}{{O}_{2}}\]                                 \[\therefore \]                         \[Cl{{O}_{2}}=2.5{{H}_{2}}{{O}_{2}}\]


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