A) 16
B) 68
C) 34
D) 17
Correct Answer: D
Solution :
\[{{H}_{2}}S\to \overset{0}{\mathop{S}}\,+2e\] Equivalent wt. = \[\frac{\text{Mol}\text{. wt}\text{.}}{\text{2}}\]=\[\frac{34}{2}\]=17.
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